247=330x+4.9x^2

Solution for 247=330x+4.9x^2 equation:

247=330x+4.9x^2

We move all terms to the left:

247-(330x+4.9x^2)=0

We get rid of parentheses

-4.9x^2-330x+247=0

a = -4.9; b = -330; c = +247;
Δ = b2-4ac
Δ = -3302-4·(-4.9)·247
Δ = 113741.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-330)-\sqrt{113741.2}}{2*-4.9}=\frac{330-\sqrt{113741.2}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-330)+\sqrt{113741.2}}{2*-4.9}=\frac{330+\sqrt{113741.2}}{-9.8}
$